Rock Mechanics Worked Examples
Layered overburden and unit conversion
Estimate total vertical stress below 100 m of rock with unit weight 24 kN/m³ over 100 m at 27 kN/m³. Assume a level, laterally extensive profile.
Step-by-Step Solution
0 of 2 Steps CompletedWater pressure and joint shear strength
A prescribed joint has total normal stress 12 MPa, water pressure 3 MPa, effective cohesion 5 MPa and effective friction angle 30°. Compare its modeled shear strength with the dry value.
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0 of 2 Steps CompletedFit a joint envelope from two shear tests
Two comparable direct-shear tests on a joint fail at effective normal/shear stresses (8, 7) and (15, 11) MPa. Fit a straight line over this tested range.
Step-by-Step Solution
0 of 2 Steps CompletedEffective Mohr circle and an oriented plane
Total principal stresses are 80 and 20 MPa; uniform joint pressure is 10 MPa with unit effective-stress coefficient. The plane normal lies in the major–minor principal section and makes 30° with the major principal stress direction. Find the effective circle and stresses on that plane.
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0 of 2 Steps CompletedTangency from the principal-stress equation
For an isotropic Mohr–Coulomb material with and , find major effective stress at failure when minor effective stress is 10 MPa.
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0 of 2 Steps CompletedHydrostatic and effective-tension limits
A prescribed total state has equal principal stresses of 20 MPa. Compare uniform joint pressure of 5 MPa with 25 MPa.
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0 of 2 Steps CompletedCompare a prescribed-plane ratio with a supplied criterion
A plane has effective normal stress 6 MPa, driving shear 4 MPa, and . Compare its ratio with a hypothetical project requirement of 1.30. No additional pore pressure is to be subtracted.
Step-by-Step Solution
0 of 2 Steps CompletedNonlinear confinement and rock-mass strength
Use prescribed Hoek–Brown constants , , and . Find major effective stress at failure for minor effective stress 10 MPa, and the rock-mass unconfined strength.
Step-by-Step Solution
0 of 2 Steps CompletedDistinguish full recovery from RQD
A 1.00 m run recovers sound pieces of 20, 8, 12, 7, 25 and 28 cm separated by natural breaks. Count pieces longer than 10 cm. Find total recovery and RQD.
Step-by-Step Solution
0 of 2 Steps CompletedRMR basic score and application adjustment
An RMR89 assessment supplies ratings of 7 for strength, 13 for RQD, 10 for spacing, 20 for condition and 10 for groundwater. The applicable orientation adjustment is . Compute basic and adjusted ratings.
Step-by-Step Solution
0 of 2 Steps CompletedQ, equivalent dimension and changing conditions
Use , , , , and . Excavation span is 10 m and the supplied ESR is 1.3. Then consider and , holding other inputs fixed.
Step-by-Step Solution
0 of 2 Steps CompletedSeparate an observed mechanism from a support prescription
Two headings have different records: A shows sudden energetic ejection from highly stressed massive rock; B shows progressive closure over weeks in weak ground, without evidence of mineral swelling. What should their assessments distinguish?