Moisture Content of Wood
The moisture content (MC) of wood drastically affects its strength,
dimensions, and susceptibility to decay. Wood in structural applications is
generally dried to an equilibrium moisture content (EMC) matching its service
environment.
Example
A sample of freshly cut Douglas Fir lumber weighs 150 grams. After being dried
in an oven at 103°C until it reaches a constant mass, its oven-dry weight is
determined to be 110 grams. Calculate the moisture content of the wood. Is
this piece considered "green" or "dry" lumber?
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Orthotropic Strength Properties of Timber
Wood is a highly orthotropic material, meaning its mechanical properties are
uniquely different in three mutually perpendicular directions: longitudinal
(parallel to the grain), radial, and tangential.
Example
A nominal 2x4 (actual dimensions ) piece of Southern Pine lumber is subjected to a compressive load. The lumber has a compressive strength parallel to the grain () of 35.0 MPa and a compressive strength perpendicular to the grain () of 4.5 MPa.
Calculate the maximum allowable compressive load () if the lumber is loaded as a short column (parallel to the grain) versus if it is loaded flat as a sill plate (perpendicular to the grain). Ignore any buckling or safety factors for this basic calculation.
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Volumetric Shrinkage of Wood
Wood shrinks significantly as it dries from its Fiber Saturation Point (FSP)
down to its Equilibrium Moisture Content (EMC). This shrinkage is unequal in
the three orthotropic directions.
Example
A freshly sawn "green" oak board has a tangential width of 200.0 mm and a radial thickness of 50.0 mm. The moisture content is 45%. The board is air-dried to a final moisture content of 12%.
The species has a total tangential shrinkage coefficient () of 8.0% and a total radial shrinkage coefficient () of 4.0%. The Fiber Saturation Point () for oak is approximately 30%.
Calculate the final dimensions of the board after drying. Ignore longitudinal shrinkage as it is typically negligible (less than 0.2%).
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