Solved Problems

Example 1: Load Combinations

Problem: A reinforced concrete beam supports a dead load of 20 kN/m20 \text{ kN/m} and a live load of 15 kN/m15 \text{ kN/m}. Calculate the critical factored design load wuw_u.

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Example 2: Modulus of Elasticity and Modular Ratio

Problem: Calculate the modulus of elasticity of normal weight concrete with fc=28 MPaf'_c = 28 \text{ MPa}. Also determine the modular ratio nn, which is used in Working Stress Design (WSD) and deflection calculations.

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Example 3: Cracking Moment

Problem: A plain concrete beam (without reinforcement) has a width of 300mm and height of 500mm. fc=28 MPaf'_c = 28 \text{ MPa}. Calculate the cracking moment McrM_{cr}.

RC Beam Section Analysis

NA (c=0.0)εc=0.003εt=0.0050
Steel Area (As)
942 mm²
Depth of Block (a)
0.0 mm
Reduction Factor (φ)
0.900
Design Capacity (φMn)
0.00 kN-m
Calculations based on NSCP 2015 / ACI 318M-19 using Rectangular Stress Block.

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Example 4: Comparing Design Load Combinations

Problem: A column supports the following service loads: D=1000 kND = 1000 \text{ kN}, L=600 kNL = 600 \text{ kN}, W=400 kNW = 400 \text{ kN}, and E=500 kNE = 500 \text{ kN}. Determine the governing ultimate factored load UU for the column design.

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Case Study 1: Structural Failure Due to Low Compressive Strength

Problem: During construction, cylinders cast from a concrete pour on the second floor yielded a 28-day compressive strength (fcf'_c) of 15 MPa, well below the specified 28 MPa. Analyze the potential consequences and required actions.

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Case Study 2: Insufficient Steel Ductility

Problem: A contractor mistakenly substituted Grade 40 (276 MPa) steel with high-strength, low-ductility steel (with no clear yield plateau and low elongation at rupture) in a seismic moment frame. Evaluate the theoretical implications for structural safety.

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