Hydrostatics: Forces on Surfaces

Calculating hydrostatic forces on plane and submerged surfaces, including magnitude and location (Center of Pressure).

Concept Overview

When a surface is submerged in a static fluid, the fluid exerts a pressure force normal to the surface. Since pressure increases with depth, the distribution of force is non-uniform.

Plane Surfaces in Submerged Fluids

Consider a plane surface of arbitrary shape with area AA, inclined at an angle θ\theta to the free surface.

Hydrostatic Force on a Rectangular Plane

Total Force (F):0.0 kN
Centroid Depth (barh\\bar{h}):0.00 m
Centroid Distance (bary\\bar{y}):0.00 m
Center of Pressure (ypy_p):0.00 m

Notice that the Center of Pressure (ypy_p), red dot) is always slightly deeper than the Centroid (bary\\bar{y}), blue dot). This eccentricity decreases as the depth increases.

C (ȳ)C (ȳ)FF

What this teaches

This simulation demonstrates how the magnitude and location of hydrostatic force on a submerged plane surface vary with depth and inclination angle. It highlights the distinction between the centroid (geometric center) and the center of pressure (point of force application).

Try this

  • Set the Incline Angle to 90° (vertical). Increase the depth from 0m to 5m. Notice how the center of pressure (red dot) gets closer to the centroid (blue dot) as depth increases, but is always below it.
  • Change the angle to 30°. Observe how the total force decreases compared to 90° at the same depth, due to a lower vertical depth to the centroid.

Magnitude of Hydrostatic Force

The total hydrostatic force on a plane surface is the product of the pressure at the centroid and the area.

Magnitude of Hydrostatic Force

Calculates the total hydrostatic force on a plane surface.

F=PcgA=γhˉAF = P_{cg} A = \gamma \bar{h} A

Variables

SymbolDescriptionUnit
FFTotal hydrostatic force.N
PcgP_{cg}Pressure at the centroid of the area.Pa
Vertical distance from the free surface to the Centroid (CC) of the area.m
Specific weight of the fluid.N/m3N/m^3
AATotal area of the surface.m2m^2

Center of Pressure (Location)

The point of application of the resultant force is called the Center of Pressure (CPCP). It is always below the centroid because pressure increases with depth.

Location along the inclined plane (ypy_p):

Center of Pressure Location

Calculates the distance from the free surface to the Center of Pressure along the incline.

yp=yˉ+IxcyˉAy_p = \bar{y} + \frac{I_{xc}}{\bar{y} A}

Variables

SymbolDescriptionUnit
ypy_pDistance from the free surface to CPCP along the incline.m
m
IxcI_{xc}Moment of Inertia of the area about the centroidal axis parallel to the free surface.m4m^4
AATotal area of the surface.m2m^2

Eccentricity

The distance between the Centroid and the Center of Pressure is called the eccentricity (ee).

Eccentricity

Calculates the distance between the centroid and the center of pressure.

e=ypyˉ=IxcyˉAe = y_p - \bar{y} = \frac{I_{xc}}{\bar{y}A}

Variables

SymbolDescriptionUnit
eeEccentricity (distance between Centroid and Center of Pressure).m
ypy_pDistance from the free surface to CPCP along the incline.m
Distance from the free surface to the Centroid along the incline.m
IxcI_{xc}Moment of Inertia of the area about the centroidal axis.m4m^4
AASubmerged area of the surface.m2m^2

Common Moments of Inertia

Common centroidal moments of inertia used in center-of-pressure calculations include:

  • Rectangle (b×hb \times h): Ixc=bh312I_{xc} = \frac{bh^3}{12}
  • Triangle (b×hb \times h): Ixc=bh336I_{xc} = \frac{bh^3}{36}
  • Circle (radius rr): Ixc=πr44I_{xc} = \frac{\pi r^4}{4}
  • Semicircle (radius rr): Ixc=0.1098r4I_{xc} = 0.1098 r^4

Parallel Axis Theorem

When calculating the moment of inertia (II) for shapes not centered on the axis of rotation, the parallel axis theorem is used.

Parallel Axis Theorem

Finding the moment of inertia about an axis parallel to the centroidal axis.

I=Ixc+Ad2I = I_{xc} + A d^2

Variables

SymbolDescriptionUnit
IIMoment of inertia about the parallel axis.m4m^4
IxcI_{xc}Moment of inertia about the centroidal axis.m4m^4
AAArea of the shape.m2m^2
ddPerpendicular distance between the centroidal axis and the parallel axis.m

Force on Curved Surfaces

For curved surfaces, it is easier to calculate the horizontal and vertical components of the force separately.

Horizontal Component (FHF_H)

The horizontal force on a curved surface is equal to the hydrostatic force on the vertical projection of the curved surface.

Horizontal Component (FHF_H)

Calculates the horizontal component of the hydrostatic force on a curved surface.

FH=γhˉprojAprojF_H = \gamma \bar{h}_{proj} A_{proj}

Variables

SymbolDescriptionUnit
FHF_HHorizontal component of hydrostatic force.N
Specific weight of the fluid.N/m3N/m^3
Vertical distance from the free surface to the centroid of the projected vertical area.m
AprojA_{proj}Area of the projected vertical surface.m2m^2

Note

Horizontal Component Action Line: The horizontal component acts at the center of pressure of the projected vertical area.

Vertical Component (FVF_V)

The vertical force is equal to the weight of the fluid volume (real or imaginary) directly above the curved surface extending to the free surface.

Vertical Component (FVF_V)

Calculates the vertical component of the hydrostatic force on a curved surface.

FV=γVaboveF_V = \gamma V_{above}

Variables

SymbolDescriptionUnit
FVF_VVertical component of hydrostatic force.N
Specific weight of the fluid.N/m3N/m^3
VaboveV_{above}Volume of fluid (real or imaginary) directly above the curved surface.m3m^3

Note

Vertical Component Action Line: The vertical component acts through the centroid of the volume.

Resultant Force and Direction

For curved surfaces, the resultant hydrostatic force and its direction are found by combining the horizontal and vertical components.

Resultant Force (RR)

Calculates the total resultant force from the horizontal and vertical components.

R=FH2+FV2R = \sqrt{F_H^2 + F_V^2}

Variables

SymbolDescriptionUnit
RRTotal resultant force.N
FHF_HHorizontal component of force.N
FVF_VVertical component of force.N

Resultant Direction (θ\theta)

Calculates the angle of the resultant force with the horizontal.

tanθ=FVFH\tan\theta = \frac{F_V}{F_H}

Variables

SymbolDescriptionUnit
Angle of the resultant force with the horizontal.rad or degrees
FHF_HHorizontal component of force.N
FVF_VVertical component of force.N

Pressure Prism Method

For rectangular plane surfaces, the hydrostatic force can be visualized and calculated using a 3D Pressure Prism. The base of the prism is the area of the surface, and the altitude (height) at any point is the pressure (P=γhP = \gamma h) at that depth.

  • Magnitude: The total force (FF) equals the volume of the pressure prism.
  • Location: The Center of Pressure (CPCP) passes through the centroid of this 3D prism volume.

This geometric approach is often simpler than using moments of inertia, especially for surfaces starting at the free surface (where the prism is a wedge and the force acts at 2/32/3 depth).

Thin-Walled Cylindrical Tanks

When a cylinder of diameter DD contains fluid at an internal pressure PP, the fluid pushes outwards, creating tension in the walls. The force tending to split the cylinder in half longitudinally is resisted by the tensile force (TT) in the pipe wall.

Hoop Tension Force

Calculates the hoop tension force per unit length along a thin-walled cylinder.

T=PD2T = \frac{P D}{2}

Variables

SymbolDescriptionUnit
TTHoop tension force per unit length along the cylinder.N/m
PPInternal fluid pressure.Pa
DDInside diameter of the cylinder.m

Circumferential Stress

The tension in the walls induces a circumferential (hoop) stress in the material.

Circumferential (Hoop) Stress

Calculates the circumferential stress in a thin-walled cylinder under internal pressure.

σc=PD2t\sigma_c = \frac{P D}{2 t}

Variables

SymbolDescriptionUnit
Circumferential (hoop) stress.Pa
PPInternal fluid pressure.Pa
DDInside diameter of the cylinder.m
ttWall thickness of the cylinder.m

Gravity Dam Stability

Gravity dams resist the hydrostatic force of water solely through their own massive weight. They are checked against three primary failure modes: Overturning, Sliding, and Bearing Capacity.

Overturning Failure Mode

Overturning: The dam rotating about its downstream "toe". The Factor of Safety against overturning (FSOFSO) is the ratio of Righting Moments (RM\sum RM) to Overturning Moments (OM\sum OM) about the toe.

Factor of Safety against Overturning

Calculates the ratio of righting moments to overturning moments about the toe.

FSO=RMOM1.5FSO = \frac{\sum RM}{\sum OM} \ge 1.5

Variables

SymbolDescriptionUnit
FSOFSOFactor of Safety against Overturning.-
Sum of righting moments about the toe.N·m
Sum of overturning moments about the toe.N·m

Sliding Failure Mode

Sliding: The dam being pushed horizontally downstream. The Factor of Safety against sliding (FSSFSS) relates frictional resistance to the driving hydrostatic force.

Factor of Safety against Sliding

Calculates the ratio of resisting frictional force to driving hydrostatic force.

FSS=μFVFH1.5FSS = \frac{\mu \sum F_V}{\sum F_H} \ge 1.5

Variables

SymbolDescriptionUnit
FSSFSSFactor of Safety against Sliding.-
Coefficient of friction between the dam base and foundation.-
Net vertical force (Weight - Uplift).N
Total horizontal hydrostatic force.N

Bearing Capacity Failure Mode

Bearing Capacity: The pressure under the base exceeding the allowable soil/rock bearing pressure, which can cause foundation settlement or crushing at the toe.

Key Takeaways
  • Centroid vs CP: The force acts at the Center of Pressure (CPCP), which is always deeper than the Centroid (CC).
  • Parallel Axis Theorem: Use I=Ixc+Ad2I = I_{xc} + A d^2 to find moments of inertia about parallel axes.
  • Curved Surfaces: Decompose into Horizontal (projection) and Vertical (weight of fluid) components.
  • Pressure Prism: For rectangular surfaces, calculate force as the volume of the pressure prism and locate it at the volume's centroid.