Example

Example: Terzaghi's Bearing Capacity for a Square Footing

A square shallow foundation is 1.5 m×1.5 m1.5 \text{ m} \times 1.5 \text{ m} in plan. It is placed at a depth (DfD_f) of 1.0 m1.0 \text{ m} in a dense sandy soil. The soil parameters are: γ=18.0 kN/m3\gamma = 18.0 \text{ kN/m}^3, c=0 kPac' = 0 \text{ kPa}, and ϕ=30\phi' = 30^\circ. The groundwater table is very deep. Using Terzaghi's equation, determine the ultimate bearing capacity (quq_u) and the allowable bearing capacity (qallowq_{allow}) with a factor of safety of 3.0.
(Given Terzaghi bearing capacity factors for ϕ=30\phi' = 30^\circ: Nc=37.16,Nq=22.46,Nγ=19.13N_c = 37.16, N_q = 22.46, N_\gamma = 19.13)

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Example

Example: The General Bearing Capacity Equation

A rectangular footing (B=2.0 mB = 2.0 \text{ m}, L=3.0 mL = 3.0 \text{ m}) is constructed at a depth of Df=1.5 mD_f = 1.5 \text{ m} in a uniform sand deposit. The water table is very deep. The soil properties are ϕ=30\phi' = 30^\circ, c=0c' = 0, and γ=18.5 kN/m3\gamma = 18.5 \text{ kN/m}^3. Using Meyerhof's general bearing capacity equation, calculate the ultimate bearing capacity (quq_u). Assume vertical loading (iq=iγ=1.0i_q = i_\gamma = 1.0) and level ground/base (dq,dγd_q, d_\gamma are ignored for simplicity here, assume =1.0= 1.0). The bearing capacity factors are Nq=18.4N_q = 18.4, Nγ=22.4N_\gamma = 22.4. The shape factors are sq=1+BLtanϕs_q = 1 + \frac{B}{L}\tan\phi' and sγ=10.4BLs_\gamma = 1 - 0.4\frac{B}{L}.

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Example

Example: Footing with Eccentric Loading

A continuous wall footing (B=2.0 mB = 2.0 \text{ m}) carries a vertical load of P=400 kN/mP = 400 \text{ kN/m} and a moment of M=100 kNcdotm/mM = 100 \text{ kN}\\cdot\text{m/m}. The footing is embedded 1.0 m1.0 \text{ m} in clay (su=c=120 kPas_u = c = 120 \text{ kPa}, ϕ=0\phi = 0, γ=18 kN/m3\gamma = 18 \text{ kN/m}^3). Determine the effective width (BB') and calculate the ultimate bearing capacity (quq_u) using Terzaghi's equation (Nc=5.7,Nq=1.0,Nγ=0N_c = 5.7, N_q = 1.0, N_\gamma = 0).

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Example

Example: Effect of Groundwater Table on Bearing Capacity

A square footing (B=2.5 mB = 2.5 \text{ m}) is founded at Df=1.0 mD_f = 1.0 \text{ m} in sand (c=0c'=0, ϕ=35\phi'=35^\circ, γdry=17 kN/m3\gamma_{dry} = 17 \text{ kN/m}^3, γsat=20 kN/m3\gamma_{sat} = 20 \text{ kN/m}^3). The groundwater table rises from a deep location to exactly the ground surface. Evaluate the percentage reduction in the ultimate bearing capacity (quq_u). (Assume Nq=33.3N_q=33.3, Nγ=48.0N_\gamma=48.0).

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Example

Case Study: Local Shear Failure in Loose Sand

A temporary grandstand was erected on large, square timber footings resting on a deposit of very loose silty sand. The designers calculated the allowable bearing capacity using general shear failure parameters, assuming a rigid, dense soil response.

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Example

Case Study: Punching Shear Failure of a Silo Foundation

A tall, heavy cylindrical steel grain silo was constructed on a thick, very soft, highly compressible clay layer underlain by bedrock. A thick concrete mat foundation was used to spread the load.

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