Geophysical Methods — Worked Examples

Original synthetic records illustrate calculations under stated assumptions. A velocity, scalar resistivity or processed anomaly is not a uniquely identified material or a completed design.

Recover Velocities from Time–Distance Slopes

A flat horizontal two-layer interpretation has a direct line through (0 m, 0 ms) and (16 m, 40 ms), and a head line through (30 m, 75 ms) and (80 m, 95 ms). Find both velocities and the extrapolated head-line intercept.

Travel-Time Slopes and Intercept

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Infer Depth from a Consistent Crossover

For a horizontal homogeneous two-layer model, V1=400 m/sV_1=400\text{ m/s}, V2=2500 m/sV_2=2500\text{ m/s} and crossover xc=30.0 mx_c=30.0\text{ m}. Find interface depth. The first-arrival curves are shown below.

Crossover for a Two-Layer Depth Inference

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Critical Offset Is Smaller than Crossover

A horizontal model has V1=500 m/sV_1=500\text{ m/s}, V2=1000 m/sV_2=1000\text{ m/s} and depth 12.0 m. The receiver is 55.0 m from the source. Find critical angle, minimum head-path offset, crossover and the first arrival.

Available Head Path and First Arrival

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Reject a Faster-Refractor Interpretation When Velocity Reverses

A proposed conventional two-layer refraction interpretation assigns V1=1500 m/sV_1=1500\text{ m/s} and V2=900 m/sV_2=900\text{ m/s}. Can its critical-angle and crossover-depth formulas be used to infer the deeper boundary?

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Convert Wenner Measurements with Their Geometry

A surface Wenner array has A, M, N and B at 0, 5, 10 and 15 m. Injected current is 100 mA and VM−VN=200 mVV_M-V_N=200\text{ mV} with the stated polarity. Calculate apparent resistivity.

Wenner AMNB Measurement Layout

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Zero Current Does Not Define Resistivity

A synthetic Wenner record lists a=5.00 ma=5.00\text{ m}, I=0 mAI=0\text{ mA} and ΔV=200 mV\Delta V=200\text{ mV}. A second record has both current and voltage zero. What should the apparent-resistivity calculator report?

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Convert a Zero-Offset Radar Time to Depth

In the stated homogeneous low-loss model, relative permittivity is 9.00 and a zero-offset two-way reflection time is 40.0 ns. Use the declared rounded c=0.300 m/nsc=0.300\text{ m/ns} to infer vertical depth.

Two-Way Radar Path Geometry

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An Offset Hyperbola Does Not Give Vertical Depth Directly

A synthetic point is 3.00 m deep. A coincident transmitter/receiver is 4.00 m laterally from directly above it. In a homogeneous medium with v=0.100 m/nsv=0.100\text{ m/ns}, find two-way time and the depth error from treating that return as vertical.

Radar Slant Range Versus Vertical Depth

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A Missing Radar Return Does Not Clear an Excavation

A planned 3 m excavation crosses saline clay. GPR shows poor penetration and no identifiable utility return. Existing utility records are incomplete. What conclusion is supported?

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Crosshole Velocity Uses Separation at Depth

A crosshole shear-wave test has an independently verified source–receiver distance of 8.00 m at the measurement depth. The corrected shear arrival is 25.0 ms after the source trigger. Calculate path-average velocity.

Borehole Timing and Actual Path Length

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Downhole Interval Velocity with a Vertical Path

A surface source lies directly above a vertical receiver hole. Corrected shear arrivals are 40.0 ms at 10.0 m and 65.0 ms at 15.0 m, using a consistent trigger. Assume the relevant path is vertical. Find interval velocity between the receivers.

Vertical Interval Travel-Time Record

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Time-Average a Complete Vs30 Profile

The upper 30 m consists of 5.00 m at 150 m/s, 10.0 m at 300 m/s and 15.0 m at 600 m/s. Calculate Vs30V_{s30} and compare with the thickness-weighted arithmetic average.

Full-Depth Shear Travel-Time Account

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Velocity Alone Does Not Prescribe an Excavation Method

A highway-cut survey reports a P-wave velocity of 3200 m/s. No equipment-specific rippability chart, discontinuity survey, weathering information or trial excavation is supplied. Must the entire cut be drilled and blasted?

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A Resistive Karst Anomaly Is a Hypothesis to Test

A synthetic resistivity inversion in limestone shows a 10000 Ω·m anomaly in a 200 Ω·m background. Sparse boreholes do not intersect it. What does this establish about a proposed foundation?

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