Geophysical Methods — Worked Examples
Recover Velocities from Time–Distance Slopes
A flat horizontal two-layer interpretation has a direct line through (0 m, 0 ms) and (16 m, 40 ms), and a head line through (30 m, 75 ms) and (80 m, 95 ms). Find both velocities and the extrapolated head-line intercept.
Step-by-Step Solution
0 of 3 Steps CompletedInfer Depth from a Consistent Crossover
For a horizontal homogeneous two-layer model, , and crossover . Find interface depth. The first-arrival curves are shown below.
Step-by-Step Solution
0 of 3 Steps CompletedCritical Offset Is Smaller than Crossover
A horizontal model has , and depth 12.0 m. The receiver is 55.0 m from the source. Find critical angle, minimum head-path offset, crossover and the first arrival.
Step-by-Step Solution
0 of 3 Steps CompletedReject a Faster-Refractor Interpretation When Velocity Reverses
A proposed conventional two-layer refraction interpretation assigns and . Can its critical-angle and crossover-depth formulas be used to infer the deeper boundary?
Step-by-Step Solution
0 of 3 Steps CompletedConvert Wenner Measurements with Their Geometry
A surface Wenner array has A, M, N and B at 0, 5, 10 and 15 m. Injected current is 100 mA and with the stated polarity. Calculate apparent resistivity.
Step-by-Step Solution
0 of 3 Steps CompletedZero Current Does Not Define Resistivity
A synthetic Wenner record lists , and . A second record has both current and voltage zero. What should the apparent-resistivity calculator report?
Step-by-Step Solution
0 of 3 Steps CompletedConvert a Zero-Offset Radar Time to Depth
In the stated homogeneous low-loss model, relative permittivity is 9.00 and a zero-offset two-way reflection time is 40.0 ns. Use the declared rounded to infer vertical depth.
Step-by-Step Solution
0 of 3 Steps CompletedAn Offset Hyperbola Does Not Give Vertical Depth Directly
A synthetic point is 3.00 m deep. A coincident transmitter/receiver is 4.00 m laterally from directly above it. In a homogeneous medium with , find two-way time and the depth error from treating that return as vertical.
Step-by-Step Solution
0 of 3 Steps CompletedA Missing Radar Return Does Not Clear an Excavation
A planned 3 m excavation crosses saline clay. GPR shows poor penetration and no identifiable utility return. Existing utility records are incomplete. What conclusion is supported?
Step-by-Step Solution
0 of 3 Steps CompletedCrosshole Velocity Uses Separation at Depth
A crosshole shear-wave test has an independently verified source–receiver distance of 8.00 m at the measurement depth. The corrected shear arrival is 25.0 ms after the source trigger. Calculate path-average velocity.
Step-by-Step Solution
0 of 3 Steps CompletedDownhole Interval Velocity with a Vertical Path
A surface source lies directly above a vertical receiver hole. Corrected shear arrivals are 40.0 ms at 10.0 m and 65.0 ms at 15.0 m, using a consistent trigger. Assume the relevant path is vertical. Find interval velocity between the receivers.
Step-by-Step Solution
0 of 3 Steps CompletedTime-Average a Complete Vs30 Profile
The upper 30 m consists of 5.00 m at 150 m/s, 10.0 m at 300 m/s and 15.0 m at 600 m/s. Calculate and compare with the thickness-weighted arithmetic average.
Step-by-Step Solution
0 of 3 Steps CompletedVelocity Alone Does Not Prescribe an Excavation Method
A highway-cut survey reports a P-wave velocity of 3200 m/s. No equipment-specific rippability chart, discontinuity survey, weathering information or trial excavation is supplied. Must the entire cut be drilled and blasted?
Step-by-Step Solution
0 of 3 Steps CompletedA Resistive Karst Anomaly Is a Hypothesis to Test
A synthetic resistivity inversion in limestone shows a 10000 Ω·m anomaly in a 200 Ω·m background. Sparse boreholes do not intersect it. What does this establish about a proposed foundation?