Site Investigation — Worked Examples
Separate TCR, SCR and RQD
A 1000 mm run yields sound full-diameter pieces of 120, 80, 250 and 100 mm, an unsound full-diameter piece of 150 mm, and fragments with an equivalent recovered length of 100 mm. Calculate the three indices using the lesson's logging convention.
Step-by-Step Solution
0 of 3 Steps CompletedThreshold Inclusion and Unrounded Classification
A 150 cm run has sound full-diameter pieces of 12, 8, 25, 5, 14, 9, 32, 11, 4 and 18 cm. Validate recovery, calculate RQD and classify the unrounded value. Would a separate sound piece exactly 10 cm long qualify?
Step-by-Step Solution
0 of 3 Steps CompletedOverburden Normalization Is a Separate Operation
A complete SPT record has already been corrected to . An applicable interpretation supplies for this layer. Find and state what the number establishes.
Step-by-Step Solution
0 of 3 Steps CompletedA Documented Mechanical Break Changes the Numerator
A 100 cm run yields sound full-diameter lengths of 5, 6, 24, 9 and 40 cm. The driller and logger document that the 5 and 6 cm pieces broke during handling, and the pieces fit as one original piece. Other breaks are natural. Determine RQD with the documented rejoining and the error if that pair is left separate.
Step-by-Step Solution
0 of 3 Steps CompletedReject an Impossible Recovery Account
A log lists a 120 cm drilled run, 56 cm of qualifying pieces and another 90 cm of nonqualifying recovered material, without overlap. Should the logger publish an RQD of ?
Step-by-Step Solution
0 of 3 Steps CompletedCombine Unequal Core Runs by Drilled Length
Two valid runs have lengths of 100 and 200 cm and RQD values of 80.0% and 50.0%, respectively. Calculate their combined RQD.
Step-by-Step Solution
0 of 3 Steps CompletedFrom a Complete SPT Record to N60
Three complete 150 mm increments require 6, 12 and 18 blows. Measured and the adopted factors are , and . Calculate field and .
Step-by-Step Solution
0 of 3 Steps CompletedPreserve Partial SPT Penetration
A log records 8 blows for 150 mm seating, 12 blows for the next 150 mm, then 50 blows for only 50 mm before termination under the governing procedure. What should be retained, and can ordinary field or be reported from this record?
Step-by-Step Solution
0 of 3 Steps CompletedRecover the Energy Ratio from a Correction
A complete test has field , corrected , and supplied , . What energy ratio is implied by this calculation, and does the result replace energy measurement?
Step-by-Step Solution
0 of 3 Steps CompletedDistinguish Percentage Points from Relative Error
A 300 cm run yields 180 cm recovery, including 150 cm of qualifying sound pieces. An analyst incorrectly divides the qualifying length by recovered length. Find the true RQD, the incorrect value, their percentage-point difference and the relative overestimate.
Step-by-Step Solution
0 of 3 Steps CompletedMatch Sampling and Drilling to the Required Evidence
A preliminary profile suggests saturated soft clay below cobbly overburden. The project needs consolidation information from the clay and confirmation of the deeper material. Select an investigation response without assuming perfect samples or a particular proprietary drilling system.
Step-by-Step Solution
0 of 3 Steps CompletedResolve a Ground-Model Conflict Before Design
Two boreholes 20 m apart recover limestone and breccia, respectively. An intervening geophysical anomaly has no direct confirmation. Historical records also suggest nearby old workings. Does this prove an active karst cavity or establish that a proposed public park is safe?