Kinetics of Rigid Bodies: Impulse and Momentum

Learning Objectives

  • Define linear and angular impulse and momentum for a rigid body.
  • Apply the principle of impulse and momentum to solve kinetics problems involving force, mass, velocity, and time.
  • Analyze systems of interacting rigid bodies.
  • Apply conservation of linear and angular momentum to collision and impact problems.
  • Understand the mechanics of eccentric impact.

This method relates forces and moments acting over a time interval to the change in both linear and angular momentum of the body. It is particularly powerful for impact problems and situations involving variable forces, providing a direct relation between time and velocity.

Civil Engineering Applications

Impulse and momentum methods are frequently applied when examining impulsive impact forces in civil structures:

  • Vehicular Collision: Analyzing impact forces of cars or ships colliding with bridge piers over short time durations.
  • Pile Driving: Studying the rapid transfer of momentum from the falling pile hammer to the driven pile.
  • Dynamic Impact: Evaluating the response of slabs when struck by dropped objects in industrial facilities.

Impulse

The integral of a force or couple moment over the time interval during which it acts. It represents the total "push" or "twist" given to a body.

Momentum

The product of a body's mass or mass moment of inertia and its corresponding velocity. Linear momentum is mvm\mathbf{v}, and angular momentum is IωI\mathbf{\omega}.

Principle of Impulse and Momentum

The principle states that the initial momentum of the system plus the sum of all external impulses acting on the system equals the final momentum of the system.

Linear Impulse-Momentum Equation

The change in linear momentum of the center of mass G is equal to the linear impulse of external forces.

m(vG)1+∑∫t1t2F dt=m(vG)2m(v_G)_1 + \sum \int_{t_1}^{t_2} \mathbf{F} \, dt = m(v_G)_2

Variables

SymbolDescriptionUnit
mmMass of the rigid bodykg
(vG)1,(vG)2(v_G)_1, (v_G)_2Initial and final velocities of the center of massm/s
F\mathbf{F}External forces acting on the bodyN
t1,t2t_1, t_2Initial and final timess
Linear Impulse Changes Center-of-Mass Momentum

Track the vector balance from the initial to final center-of-mass momentum over the impact interval.

Use the vector equation m v_G1 + ΣJ_ext = m v_G2 component by component. Momentum is conserved in a component only when the net external impulse in that component is zero or negligible.
Initial momentum of the center of mass
Add the net external force impulse over the interval
Obtain final center-of-mass momentum

Angular Impulse-Momentum Equation

The change in angular momentum about the center of mass G is equal to the angular impulse of external moments about G.

IGω1+∑∫t1t2MG dt=IGω2I_G \omega_1 + \sum \int_{t_1}^{t_2} M_G \, dt = I_G \omega_2

Variables

SymbolDescriptionUnit
IGI_GMass moment of inertia about the center of masskg·m²
ω1,ω2\omega_1, \omega_2Initial and final angular velocitiesrad/s
MGM_GExternal moments about the center of massN·m
t1,t2t_1, t_2Initial and final timess
Angular Impulse Changes Spin About G

Relate the angular impulse of external moments about the center of mass to the change in angular momentum.

For planar motion, use H_G = I_Gω. Angular momentum about G is conserved only when the net external moment impulse about G is zero or negligible.
Initial angular momentum about G
Add external moment impulse about G
Obtain final angular momentum about G

Angular Momentum (HH)

Angular momentum represents the quantity of rotation of a body, which is the product of its moment of inertia and its angular velocity.

Angular Momentum About Center of Mass

Calculates angular momentum about the center of mass G.

HG=IGωH_G = I_G \omega

Variables

SymbolDescriptionUnit
HGH_GAngular momentum about Gkg·m²/s
IGI_GMass moment of inertia about Gkg·m²
ω\omegaAngular velocityrad/s

Angular Momentum About a Fixed Axis Through O

For planar rigid-body rotation about a fixed axis through O, angular momentum about O is the mass moment of inertia about that same axis times the signed angular velocity.

HO=IOωH_O = I_O \omega

Variables

SymbolDescriptionUnit
HOH_OAngular momentum about fixed point Okg·m²/s
IOI_OPlanar mass moment of inertia about the fixed axis through Okg·m²
ω\omegaAngular velocityrad/s

System of Rigid Bodies

When multiple rigid bodies interact, the principles of linear and angular impulse-momentum can be applied to the entire system.

System of Interacting Bodies

For a system of interacting rigid bodies, the internal forces between them generate equal and opposite impulses that sum to zero. Therefore, only external forces create a net impulse on the system.

Linear Impulse-Momentum for a System

The total linear momentum of the system is the sum of the linear momenta of each individual body.

(Lsys)1+∑∫t1t2Fextdt=(Lsys)2(\mathbf{L}_{sys})_1 + \sum \int_{t_1}^{t_2} \mathbf{F}_{ext} dt = (\mathbf{L}_{sys})_2

Variables

SymbolDescriptionUnit
(Lsys)1,(Lsys)2(\mathbf{L}_{sys})_1, (\mathbf{L}_{sys})_2Initial and final total linear momenta of the systemkg·m/s
Fext\mathbf{F}_{ext}External forces acting on the systemN
t1,t2t_1, t_2Initial and final timess

Angular Impulse-Momentum for a System

The total angular momentum of the system about a fixed point O is the sum of the angular momenta of each body about O.

(Hsys)1+∑∫t1t2(MO)extdt=(Hsys)2(\mathbf{H}_{sys})_1 + \sum \int_{t_1}^{t_2} (M_O)_{ext} dt = (\mathbf{H}_{sys})_2

Variables

SymbolDescriptionUnit
(Hsys)1,(Hsys)2(\mathbf{H}_{sys})_1, (\mathbf{H}_{sys})_2Initial and final total angular momenta about Okg·m²/s
(MO)ext(M_O)_{ext}External moments about O acting on the systemN·m
t1,t2t_1, t_2Initial and final timess

Conservation of Momentum

The conservation laws are powerful when analyzing the interaction of bodies where external impulses are negligible, such as during collisions or explosions in free space.

Conservation of Linear Momentum

If there is no net external linear impulse acting on the system (∑∫F dt=0\sum \int \mathbf{F} \, dt = 0), then the total linear momentum is conserved.

Conservation of Linear Momentum Equation

Expresses that the initial total linear momentum equals the final total linear momentum.

L1=L2\mathbf{L}_1 = \mathbf{L}_2

Variables

SymbolDescriptionUnit
L1\mathbf{L}_1Total initial linear momentumkg·m/s
L2\mathbf{L}_2Total final linear momentumkg·m/s

Conservation of Angular Momentum

If there is no net external angular impulse acting about a point P (∑∫MP dt=0\sum \int M_P \, dt = 0), then the total angular momentum about that point is conserved. This often occurs when all external forces pass through a common point P or are zero.

Conservation of Angular Momentum Equation

Expresses that the initial total angular momentum about P equals the final total angular momentum about P.

(HP)1=(HP)2(\mathbf{H}_P)_1 = (\mathbf{H}_P)_2

Variables

SymbolDescriptionUnit
(HP)1(\mathbf{H}_P)_1Total initial angular momentum about point Pkg·m²/s
(HP)2(\mathbf{H}_P)_2Total final angular momentum about point Pkg·m²/s

Eccentric Impact

Eccentric Impact

An eccentric impact occurs when the line of action of the impulsive forces acting on a rigid body does not pass through its center of mass, resulting in both translation and rotation.

When a rigid body is subjected to an eccentric impact, it undergoes a change in both translational and rotational velocity.

Eccentric Impact Principles

  • The point of impact experiences a large impulsive force ∫Fdt\int \mathbf{F} dt.
  • This impulsive force changes the linear momentum: m(vG)1+∫Fdt=m(vG)2m(\mathbf{v}_G)_1 + \int \mathbf{F} dt = m(\mathbf{v}_G)_2.
  • Because the line of impact does not pass through the center of mass GG, the force creates an angular impulse, changing the angular momentum: IGω1+∫r×Fdt=IGω2I_G \omega_1 + \int \mathbf{r} \times \mathbf{F} dt = I_G \omega_2.
  • If the object is constrained by a pin, analyzing angular momentum about the fixed pivot eliminates the need to solve for the unknown pin reaction impulses.
Why Moments About the Fixed Pivot Remove Its Reaction Impulse

Compare the moment arm of the pivot reaction impulse with the eccentric impact impulse.

For planar rotation about a fixed point P, H_P = I_Pω. This simplification requires P to remain fixed during the impact interval.
Take moments about G
  • The pin reaction impulse can have a moment arm from G
  • Its angular impulse may remain unknown
Take moments about fixed P
  • The pin reaction impulse passes through P
  • Its moment about P is zero; the eccentric impact impulse contributes r_Q/P × J_Q
Rigid-Body Impact: Impulse–Momentum Equation Selection

Choose the linear and angular impulse–momentum equations that match the impact unknowns and constraints.

Keep external force and moment impulses unless their resultants are zero or negligible over the impact interval in the selected direction or about the selected point. For planar rotation about a fixed pivot P, angular momentum is H_P = I_P ω; an impulsive reaction whose line of action passes through P has zero moment about P. This pivot simplification requires P to remain fixed during the interval.

Rigid-Body Impact: Impulse–Momentum Equation SelectionChoose the linear and angular impulse–momentum equations that match the impact unknowns and constraints.. Keep external force and moment impulses unless their resultants are zero or negligible over the impact interval in the selected direction or about the selected point. For planar rotation about a fixed pivot P, angular momentum is H_P = I_P ω; an impulsive reaction whose line of action passes through P has zero moment about P. This pivot simplification requires P to remain fixed during the interval.. Start rigid-body impact analysis → Set system, impact interval, axes, constraints, and unknowns; Set system, impact interval, axes, constraints, and unknowns → Is center-of-mass velocity change needed?; Is center-of-mass velocity change needed? — Yes → Write linear impulse–momentum about G; Is center-of-mass velocity change needed? — No → No linear velocity unknown; continue to angular check; Write linear impulse–momentum about G → Is external linear impulse negligible in the component?; Is external linear impulse negligible in the component? — Yes → Conserve total linear momentum in this component; Is external linear impulse negligible in the component? — No → Retain external linear impulse; Conserve total linear momentum in this component → Is angular velocity change needed?; Retain external linear impulse → Is angular velocity change needed?; No linear velocity unknown; continue to angular check → Is angular velocity change needed?; Is angular velocity change needed? — Yes → Is there a fixed pivot with an unknown reaction impulse through it?; Is angular velocity change needed? — No → No angular velocity unknown; solve selected relations; Is there a fixed pivot with an unknown reaction impulse through it? — Yes → Use angular impulse–momentum about fixed P; Is there a fixed pivot with an unknown reaction impulse through it? — No → Use angular impulse–momentum about G; Use angular impulse–momentum about fixed P → Is net external moment impulse about the chosen point negligible?; Use angular impulse–momentum about G → Is net external moment impulse about the chosen point negligible?; Is net external moment impulse about the chosen point negligible? — Yes → Conserve angular momentum about the chosen point; Is net external moment impulse about the chosen point negligible? — No → Retain external moment impulse; Conserve angular momentum about the chosen point → Solve selected equations; check signs and units; Retain external moment impulse → Solve selected equations; check signs and units; No angular velocity unknown; solve selected relations → Solve selected equations; check signs and units; Solve selected equations; check signs and units → Impact response determined

Start rigid-body impact analysis → Set system, impact interval, axes, constraints, and unknowns; Set system, impact interval, axes, constraints, and unknowns → Is center-of-mass velocity change needed?; Is center-of-mass velocity change needed? — Yes → Write linear impulse–momentum about G; Is center-of-mass velocity change needed? — No → No linear velocity unknown; continue to angular check; Write linear impulse–momentum about G → Is external linear impulse negligible in the component?; Is external linear impulse negligible in the component? — Yes → Conserve total linear momentum in this component; Is external linear impulse negligible in the component? — No → Retain external linear impulse; Conserve total linear momentum in this component → Is angular velocity change needed?; Retain external linear impulse → Is angular velocity change needed?; No linear velocity unknown; continue to angular check → Is angular velocity change needed?; Is angular velocity change needed? — Yes → Is there a fixed pivot with an unknown reaction impulse through it?; Is angular velocity change needed? — No → No angular velocity unknown; solve selected relations; Is there a fixed pivot with an unknown reaction impulse through it? — Yes → Use angular impulse–momentum about fixed P; Is there a fixed pivot with an unknown reaction impulse through it? — No → Use angular impulse–momentum about G; Use angular impulse–momentum about fixed P → Is net external moment impulse about the chosen point negligible?; Use angular impulse–momentum about G → Is net external moment impulse about the chosen point negligible?; Is net external moment impulse about the chosen point negligible? — Yes → Conserve angular momentum about the chosen point; Is net external moment impulse about the chosen point negligible? — No → Retain external moment impulse; Conserve angular momentum about the chosen point → Solve selected equations; check signs and units; Retain external moment impulse → Solve selected equations; check signs and units; No angular velocity unknown; solve selected relations → Solve selected equations; check signs and units; Solve selected equations; check signs and units → Impact response determined

  • Start rigid-body impact analysis: terminator
  • Set system, impact interval, axes, constraints, and unknowns: process
  • Is center-of-mass velocity change needed?: decision
  • Write linear impulse–momentum about G: process
  • Is external linear impulse negligible in the component?: decision
  • Conserve total linear momentum in this component: process
  • Retain external linear impulse: process
  • No linear velocity unknown; continue to angular check: process
  • Is angular velocity change needed?: decision
  • Is there a fixed pivot with an unknown reaction impulse through it?: decision
  • Use angular impulse–momentum about fixed P: process
  • Use angular impulse–momentum about G: process
  • Is net external moment impulse about the chosen point negligible?: decision
  • Conserve angular momentum about the chosen point: process
  • Retain external moment impulse: process
  • No angular velocity unknown; solve selected relations: process
  • Solve selected equations; check signs and units: process
  • Impact response determined: terminator

Interactive Simulation

Interact with the simulation below to explore eccentric impact on a rod.

Angular Momentum: Bullet Striking a Rod

System Parameters

Angular Momentum Solver

Conservation of HOH_O:
mv0d=Itotal ωm v_0 d = I_{\text{total}}\,\omega
Itotal=13ML2+md2I_{\text{total}} = \tfrac{1}{3}ML^2 + md^2
=1.333+0.0025=1.3358 kg⋅m2= 1.333 + 0.0025 = 1.3358\,\text{kg·m}^2
H0=2.0000 kg⋅m2/sH_0 = 2.0000\,\text{kg·m}^2/\text{s}
ω=1.50 rad/s\omega = 1.50\,\text{rad/s}
KE before:800.0 J
KE after:1.5 J
Energy lost:798.5 J (99.8%)
Bullet–Rod Angular Momentum WorkspaceO (Pivot)Ld = 0.50mReady — click Fire!
Bullet (m = 0.010 kg)
Rod (M = 4 kg)
Impact point d = 0.50 m
Key Takeaways
  • Impulse-Momentum Principle (L1+ΣI=L2L_1 + \Sigma I = L_2) applies to both linear (mvmv) and angular (IωI\omega) momentum.
  • System of Rigid Bodies: Internal impulses cancel; only external forces and moments change the total linear and angular momentum.
  • Angular Momentum (H=IωH = I\omega) is conserved when the net external moment is zero.
  • Impact Problems often use conservation of angular momentum about a fixed pivot to eliminate unknown reaction impulses.
  • Eccentric Impact imparts both a linear velocity change and a rotational velocity change due to the moment arm of the impulse.