Practical Example: Bisection Method

Finding the Root of a Simple Polynomial

Problem Statement: Find an approximate root of the function f(x)=x34x9f(x) = x^3 - 4x - 9 using the Bisection Method. Perform two iterations, starting with the interval [2,3][2, 3].

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Practical Example: Bisection Method (Advanced)

Bisection with Exponential Functions

Problem Statement: Find an approximate root of f(x)=ex3xf(x) = e^x - 3x using the Bisection Method. Perform two iterations, starting with the interval [0,1][0, 1].

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Bisection Error Analysis

Problem Statement: You are using the Bisection Method on the interval [1,2][1, 2]. Calculate the absolute maximum error bound after 4 complete iterations.

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Practical Example: Newton-Raphson Method

Accelerating Root Finding using Derivatives

Problem Statement: Find an approximate root of the function f(x)=x22f(x) = x^2 - 2 (which calculates 2\sqrt{2}) using the Newton-Raphson Method. Perform two iterations, starting with an initial guess x0=1.5x_0 = 1.5.

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Practical Example: Numerical Integration (Trapezoidal Rule)

Approximating the Area under a Curve

Problem Statement: Approximate the definite integral 02x2dx\int_0^2 x^2 dx using the Trapezoidal Rule with n=4n = 4 subintervals.

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Practical Example: Ordinary Differential Equations (ODEs)

Estimating Values with Euler's Method

Problem Statement: Solve the ordinary differential equation dy/dx=x+ydy/dx = x + y with the initial condition y(0)=1y(0) = 1 using Euler's Method. Estimate y(0.2)y(0.2) using a step size h=0.1h = 0.1.

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Practical Example: Simpson's 1/3 Rule

Higher-Order Integration Accuracy

Problem Statement: Approximate the definite integral 02x2dx\int_0^2 x^2 dx using Simpson's 1/3 Rule with n=4n = 4 subintervals. Compare the result to the Trapezoidal rule approximation (2.75).

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Practical Example: Gaussian Elimination

Solving a 2x2 System of Equations

Problem Statement: Solve the following system of linear equations using Gaussian Elimination to transform the augmented matrix into upper triangular (Row Echelon) form, followed by back-substitution.
2x+y=52x + y = 5 4x+3y=114x + 3y = 11

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