Chemical Equilibrium Examples

Equilibrium Constants

Example

Solubility Product Constant (KspK_{sp}) of Gypsum

Calculate the solubility of Calcium Sulfate (CaSO4CaSO_4, gypsum) in pure water at 25C25^\circ\text{C} if its KspK_{sp} is 4.93×1054.93 \times 10^{-5}. Express the answer in g/L\text{g/L} (Molar mass =136.14g/mol= 136.14 \, \text{g/mol}).

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