Word Problems

Word problems translate real-world situations into algebraic equations. They are an essential part of mathematics, bridging the gap between abstract algebra and practical application. In this section, we cover five common types of word problems: Age, Mixture, Work, Motion (Distance-Rate-Time), and Clock problems.

General Strategy

How to Solve Word Problems

  • Read Carefully: Read the problem multiple times. Identify what you are asked to find.
  • Assign Variables: Let a letter (e.g., xx) represent the unknown quantity. If there are multiple unknowns, try to express them all in terms of a single variable, or use multiple variables and set up a system of equations.
  • Translate to Algebra: Look for keywords (e.g., "is", "more than", "product of") and translate the English sentences into mathematical equations. Organizing data in a table is often highly effective.
  • Solve: Use appropriate algebraic techniques to solve the equation(s).
  • Check: Verify that your answer makes sense in the context of the original problem (e.g., age cannot be negative).

1. Age Problems

Age problems involve comparing the ages of people at different points in time (past, present, and future).

Key Concepts for Age Problems

  • Let the current age be represented by a variable (e.g., xx).
  • For age yy years ago, subtract yy: (xy)(x - y).
  • For age yy years from now (in the future), add yy: (x+y)(x + y).
  • It is extremely helpful to set up a table with columns for Past, Present, and Future ages.

2. Mixture Problems

Mixture problems occur when two or more substances with different concentrations, prices, or properties are combined to form a single blend.

Key Concepts for Mixture Problems

  • Amount of active ingredient: (Volume or Mass)×(Concentration %)(\text{Volume or Mass}) \times (\text{Concentration \%}).
  • The sum of the parts equals the whole: V1+V2=VtotalV_1 + V_2 = V_{\text{total}}.
  • The sum of the active ingredients equals the total active ingredient: (V1×C1)+(V2×C2)=(Vtotal×Cfinal)(V_1 \times C_1) + (V_2 \times C_2) = (V_{\text{total}} \times C_{\text{final}}).

3. Work Problems

Work problems involve people or machines doing a job together at different rates. The key is to determine how much of the job each entity can complete in one unit of time.

Work Rate Formula

Relationship between work rate, time, and job completion.

W=R×tW = R \times t

Variables

SymbolDescriptionUnit
RRRate of work (Job/Time)-
ttTime worked-
WWAmount of work completed (1 = complete job)-

Combining Work Rates

If Person A can finish a job in aa hours, their rate is 1a\frac{1}{a} job per hour. If Person B can finish in bb hours, their rate is 1b\frac{1}{b} job per hour. Working together for tt hours to complete 1 entire job:
(1a+1b)t=1orta+tb=1 \left(\frac{1}{a} + \frac{1}{b}\right)t = 1 \quad \text{or} \quad \frac{t}{a} + \frac{t}{b} = 1

4. Motion (Distance-Rate-Time) Problems

Motion problems involve objects moving at steady or average speeds. They rely on the fundamental kinematic equation.

Distance Formula

Relationship between distance, rate, and time.

d=r×td = r \times t

Variables

SymbolDescriptionUnit
ddDistance traveled-
rrRate (speed)-
ttTime-

Interactive Motion Visualizer

Use this interactive visualizer to understand how different rates affect distance over time in pursuit or opposing motion scenarios.

Distance-Rate-Time Visualizer (Catch Up Problem)

A
Dist A: 80.0 miles
B
Dist B: 0.0 miles

Live Statistics

  • Time passed since B started: 0.00 hours
  • Total time A traveled: 2.00 hours
  • Distance between them: 80.0 miles

5. Digit Problems

Digit problems involve finding unknown numbers given conditions about the sums, differences, or reversals of their individual digits.

Representing Digits

  • Let tt be the tens digit and uu be the units (ones) digit.
  • The value of the original two-digit number is 10t+u10t + u.
  • If the digits are reversed, the new number's value becomes 10u+t10u + t.
  • Example: If a number is 45, t=4t=4 and u=5u=5. The value is 10(4)+5=4510(4) + 5 = 45. Reversed is 10(5)+4=5410(5) + 4 = 54.

6. Investment and Interest Problems

These problems involve calculating the return on investments spread across multiple accounts with different interest rates.

Simple Interest Formula

Calculates the total interest earned over a period of time.

I=P×r×tI = P \times r \times t

Variables

SymbolDescriptionUnit
IITotal Interest Earned-
PPPrincipal (Initial Amount Invested)-
rrAnnual Interest Rate (as a decimal)-
ttTime (in years)-

Investment Strategy

  • Create a table with columns for Principal (PP), Rate (rr), Time (tt), and Interest (II).
  • If a total amount TT is split into two investments, let one be xx and the other be (Tx)(T - x).
  • Set up an equation equating the sum of the individual interests to the total interest earned.

7. Clock Problems

Clock problems involve determining the relative positions of the hands of a clock. They are a specialized type of distance-rate-time problem where distance is measured in degrees or minute-spaces.

Clock Fundamentals

  • The face of a clock is a circle of 360360^{\circ}.
  • The minute hand moves 360360^{\circ} in 60 minutes. Its rate is 36060=6/min\frac{360^{\circ}}{60} = \mathbf{6^{\circ}/\text{min}}.
  • The hour hand moves 3030^{\circ} (from one number to the next) in 60 minutes. Its rate is 3060=0.5/min\frac{30^{\circ}}{60} = \mathbf{0.5^{\circ}/\text{min}}.
  • Relative Rate: The minute hand gains 60.5=5.56^{\circ} - 0.5^{\circ} = \mathbf{5.5^{\circ}} on the hour hand every minute.
Key Takeaways
  • Age Problems: Always express past/future ages relative to present age variables before forming the main equation.
  • Mixture Problems: The core equation balances the total amount of the active ingredient across all mixed components.
  • Work Problems: Use the reciprocals of time. Rates are additive (1/A+1/B=1/Ttogether1/A + 1/B = 1/T_{\text{together}}).
  • Motion Problems: d=r×td = r \times t. Drawing a sketch of the paths is crucial for determining if distances should be equated, added, or subtracted.
  • Clock Problems: Treat them as circular pursuit problems. The minute hand catches up to the hour hand at a relative speed of 5.55.5^{\circ} per minute.